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48x=-3x^2-189
We move all terms to the left:
48x-(-3x^2-189)=0
We get rid of parentheses
3x^2+48x+189=0
a = 3; b = 48; c = +189;
Δ = b2-4ac
Δ = 482-4·3·189
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-6}{2*3}=\frac{-54}{6} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+6}{2*3}=\frac{-42}{6} =-7 $
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